Find the length of a curve given by the equations $x^2+y^2+z^2=1$ and $(x^2+y^2)^2=x^2-y^2$
I tried with polar parametrization and with spherical parametrization but I can't solve the definite integral that I come up with.
Find the length of a curve given by the equations $x^2+y^2+z^2=1$ and $(x^2+y^2)^2=x^2-y^2$
I tried with polar parametrization and with spherical parametrization but I can't solve the definite integral that I come up with.
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$x(t) =r\cos t = \sqrt{\cos 2t}\cos t $
$y(t) =r\cos t = \sqrt{\cos 2t}\sin t $
$z(t) =\pm\sqrt{1-x^2 -y^2}=\pm\sqrt{1-\cos 2t}=\pm \sqrt{2}|\sin 2t|$