Find the length of the parametric curve
$$x = t$$ $$y = f(t)$$
$$f(t) = \int_0^t {s \over (s^2-1)} \ \mathrm{d}s$$
$$0\leq t \leq 1/2$$
First I create the $x'$and $y'$
Then put it into the formula for parametric curves
$$L = \int_0^{1/2} \sqrt{1^2+{t^2\over (t^2-1)^2}} \ dt$$
Now this is where I'm stuck, I've tried with wolfram alpha and everything but I just can't seem to solve it.