I have done right here...
$$\lim_{n \to \infty } \frac{2^{n-1} + 3^n}{4^n - 1}.$$
I know that I have to eliminate the lowest exponents in each part which is $2^{n-1}$ at the numerator and $1$ at the denominator but how to eliminate it?
I have done right here...
$$\lim_{n \to \infty } \frac{2^{n-1} + 3^n}{4^n - 1}.$$
I know that I have to eliminate the lowest exponents in each part which is $2^{n-1}$ at the numerator and $1$ at the denominator but how to eliminate it?
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Just divide numerator and denominator by $4^{n}$. Can you now see that the limit is $0$?