Ok so far I know that first I am supposed to find angle ABC and angle ACB using the law of sines sinA/a=SinB/b=SinC/c . So that is what I did I got $sinABC/159 = sin71.5/15$. I got ABC is 71.5 yet I know I might not be right so how do I find ABC and ACB?
ABC = 180 - CAB - ACB. You know CAB.
ACB = BCD - ACD.
ACD = ACB.
So ACB = BCD - ACB = 37 13'
BCD = BAD.
So, ABC = 180 - CAB - (BAD - CAB) = 180 - BAD = 108 31'