Find the measurement of unknown angle in the given circle with centre at $O$.
My Attempt $1$. $\angle QRS=\angle PQR$
$2$. $\angle PQR=\angle PMR$.
I am struck here. Please help me with this problem..
Thanks
We have that $\angle PMQ = 90^{\circ}$ as $PQ$ is the diameter of the circle. Now additionally we have that $\angle QMS = \angle PMR$. So using this we have:
$$\angle PMR = \frac{90^{\circ} - 60^{\circ}}{2} = 15^{\circ}$$
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We have that $\angle PMQ = 90^{\circ}$ as $PQ$ is the diameter of the circle. Now additionally we have that $\angle QMS = \angle PMR$. So using this we have:
$$\angle PMR = \frac{90^{\circ} - 60^{\circ}}{2} = 15^{\circ}$$