After expanding the above term binomially, I can well guess that the majority terms are irrational, but i'm unable to find any proper method of solving this sum, after repeated trials.
Please help
Thank You
After expanding the above term binomially, I can well guess that the majority terms are irrational, but i'm unable to find any proper method of solving this sum, after repeated trials.
Please help
Thank You
Hint: The binomial sum is $$\sum_{k = 0}^{100} {100 \choose k} 3^{k/5}7^{(100-k)/3},$$ and the rational terms are exactly the integer terms, i.e., when both $k/5$ and $(100-k)/3$ are integers.