Find the orbits of the set $X=\left \{ 1,2,3 \right \}$ under $S_{3}$.
The answer is $O_{1}=O_{2}=O_{3}=\left \{ 1,2,3 \right \}$, but I do not understand why?
Find the orbits of the set $X=\left \{ 1,2,3 \right \}$ under $S_{3}$.
The answer is $O_{1}=O_{2}=O_{3}=\left \{ 1,2,3 \right \}$, but I do not understand why?
For each $x$ and each $y\in\{1,2,3\}$, there is a permutation $\rho\in S_3$ such that $\rho(x)=y$.
Such a group action is called transitive.