Find the orthogonal trajectory to the family of curves $x^2+y^2=4c^2$ where $c$ is a constant.

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Differentiate w.r.t $x$:

$$x+y\frac{dx}{dy}=4c^2$$

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$$x+yy'=0$$ turns to

$$x-\frac y{y'}=0$$ which integrates as $$y=cx.$$

This was expected as the given family is made of circles centered at the origin.