I got this answer, and was told it is partially wrong. Should I break it down further?
Two factors have a product of $3\times9^{2x}-6\times27^x$. One of the factors is $3^x-2$. What is the other factor?
Here is what I did: $$3\times9^{2x}-6\times27^x=3\times9^x\times9^x-6\times3^x\times9^x=3\times9^x(9^x-2\times3^x)=3\times9^x\times3^x(3^x-2)$$
So the other factor is $=3\times27^x$