Problem
A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:
(A) 1 km/hr; (B): 1.5 km/hr; (C): 2 km/hr; (D): 2.5 km/hr
Progress
I don't know how to solve these. Anybody can help me with these. Book answer is 1km/hr
Answer:
V = speed of the boat U = speed of the stream
$(V+U).t =4$
$(V-U)*t = 3$
$\frac{(V+U)}{(V-U)} = \frac{4}{3}$
Solving this you get $V = 7U$
$(V+U)*t_1 = 48$
$(V-U)*t_2 = 48$
$t_1 + t_2 = 14$
$8U*t_1 = 48$
$6U*t_2 = 48$
$\frac{48}{8U} + \frac{48}{6U} = 14$
Solving this we get U = 1
Thanks
Satish