Find the value $\int_{-\frac\pi8}^{\frac\pi8}[|x|+\tan(2x)]^2{\rm d}x$

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$$\int_{-\frac\pi8}^{\frac\pi8}[|x|+\tan(2x)]^2{\rm d}x$$

I am a newbie to calculus and I have no idea on how to do this question. Please help. Thanks a lot!