$\dfrac{3+x}{2022}+\dfrac{2+x}{2023}+\dfrac{1+x}{2024}+\dfrac{x}{2025}=-4$ $(S:x=-2025)$
Solving in the usual way we find the solution. I would like to know if there is a more practical way of solving this without using least common multiple.
2026-02-23 05:12:20.1771823540
Find the value of x in the equation below
91 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in ALGEBRAIC-EQUATIONS
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