Find the volume of the solid bounded by the surfaces
$x = 1 − y^{2}$ , $x = −1$ and $z^{2} = 1 − x$
I am having a bit of difficulty setting up the bounds for this question.
So far I have got:
$-1 \leqslant x \leqslant 1-y^{2}$
$-\sqrt{2} \leqslant y \leqslant \sqrt{2}$
- $-\sqrt{2} \leqslant z \leqslant \sqrt{2}$
Can someone please confirm if I am on the right track?
$$ V=\int_{-\sqrt 2}^{\sqrt 2} \int_{-1}^{1-y^2} \int_{-\sqrt {1-x}}^{\sqrt {1-x}} dz \;dx\;dy $$