Find volume of solid bounded by $z=x+y,(x^2+y^2)^2=2xy,z=0,(x>0,y>0)$

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Moving into polar coordinates find volume of solid bounded by given surfaces.

$z=x+y,(x^2+y^2)^2=2xy,z=0,(x>0,y>0)$

Moving into polar coordinates we get. $z=r(cos\phi+sin\phi),r^2=sin(2\phi),z=0$

$r(cos\phi+sin\phi)=0$ $\to$ $r=0$ or $\phi=\frac{3\pi}{4}$

But I am having trouble how to set up bounds for $r$ and $\phi.$ enter image description here

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Set up the volume integration as follows $$ \int_0^{\pi/2} \int_0^{\sqrt{\sin 2\phi}}z \ rdr d\phi= \int_0^{\pi/2} \int_0^{\sqrt{\sin 2\phi}}(\sin \phi+\cos \phi) r^2dr d\phi= \frac\pi8 $$