I wish to find the surface area cut from the sphere $x^2+y^2+z^2=2$ and the cylinder $x^2+y^2=1$
Here is what i tried: by uniting the 2 equations we get: $z=1$
The shape looks like a dome, when:
$0\lt z\lt 1$
$0\lt r\lt \sqrt 2$
$0\lt \theta \lt 2\pi$
I'm not sure how to continue from here. any suggestions?
The cylinder cuts out two spherical caps from the sphere. The radius of the sphere is $\sqrt 2$, and the two planes defining these caps have equations $z=\pm1$. It follows that the height of these caps is $\sqrt{2}-1$. By a standard theorem (maybe found out by Archimedes) the area of each cap is equal to the area of a cylinder enveloping the sphere around the equator, enclosed between the planes $z=1$ and $z=\sqrt{2}$. It follows that the area per cap is $2\pi\,\sqrt{2}(\sqrt{2}-1)=2\pi(2-\sqrt{2})$.