Instruction says
Find |3 - $\sqrt{10}$|
Given answer is $\sqrt{10}$ - 3
I cannot give an explanation.
$3^2=9<10$, so $3<\sqrt{10}$. This means that $3-\sqrt{10}<0$.
Then, by the definition of absolute value, $|3-\sqrt{10}|=-(3-\sqrt{10})=\sqrt{10}-3$
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$3^2=9<10$, so $3<\sqrt{10}$. This means that $3-\sqrt{10}<0$.
Then, by the definition of absolute value, $|3-\sqrt{10}|=-(3-\sqrt{10})=\sqrt{10}-3$