Finding an absolute value

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Instruction says

Find |3 - $\sqrt{10}$|

Given answer is $\sqrt{10}$ - 3

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$3^2=9<10$, so $3<\sqrt{10}$. This means that $3-\sqrt{10}<0$.

Then, by the definition of absolute value, $|3-\sqrt{10}|=-(3-\sqrt{10})=\sqrt{10}-3$