Using $r(x) = \frac{(1-2x)}{3}$
my first generating curve is
$y^2 + z^2 = \left(\frac{1-2x}{3}\right)^2$
I'm stuck on finding another generating curve as $x^2$ cannot be isolated to make a generating curve that revolves about $z$ axis or $y$ axis. Unless I am missing something?

I've got it guys, the correct answer was just to use the xy trace formula and have it revolve around the x-axis so
y = (1 - 2x)/3