Seems straight-forward but i can't get it right;
I have this implicit equation: $$-2 \arctan{ \left( \frac{\sqrt{y-y^2}}{y} \right) } -x=c$$
where c is a constant.
I've to find the explicit equation for $y$... The solution given in the book is $y= \sin^2{\left(\frac{x}{2}+c'\right)}$
where $c'$ is a function of $c$. However my result is $y=\cos^2{\left(\frac{x}{2}+c'\right)}$ So..where's the mistake?
just use $\sin(\theta + \pi/2)=\cos(\theta)$ and change slightly your $c'$ to get the same form as the book.