Am trying to find the coordinates of the points where the tangent is horizontal
on this equation:
y = 4 + (x-5)^6
I have worked it to this point with the chain rule
y'=6(x-5)^5
however am unable to find the x coordinates.
Any help appreciated thanks =)
2026-03-05 16:39:30.1772728770
Finding coordinates with functions that have high powers
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we have $$y'=6(x-5)^5=0$$ if $$x=5$$ to find the find the Point we get $$f(5)=4$$