Tracy and Kelly take a taxi together so they can split the bill. Since Tracy got picked up first, her share is 4 dollars more than Kelly's share. They also had 2 more charges. They had an airport fee of 4 dollars since they were dropped off at the airport, and also had an extra charge of 10% of their total fare since they were being picked up that night.
If x is the taxi fare each had to pay for the ride, which of the following shows the cost they'd have to pay if they split costs evenly.
A) $1.1x+2.2$
B) $1.1x+6.6$
C) $2.2x+2.2$
D) $2.2x+4.4$
(btw, this is what it says - no typos when I wrote it here)
When I tried it, I said this:
T(racy) = K(elly) + 4
$(T + K + 4) 1.1 =$ total cost
$(K + 4 + K + 4) 1.1 =$ total cost
$2(K + 4) 1.1 =$ total cost
And so each would pay $(K+4)1.1 = 1.1K + 4.4$ … but that's not one of the options?
The wording of the question is ambiguous and unclear, but I'll take a stab at providing an interpretation. When Tracy and Kelly arrive at the airport, the meter in the cab shows a fare of $F$, but there is an additional $4$-dollar airport fee, and then a $10\%$ surcharge on everything. Thus the total cost of the ride is
$$1.1(F+4)$$
so if Tracy and Kelly split the total cost equally (even though Tracy got picked up first), they each pay
$$1.1(F+4)/2$$
Now I'm going to assume that $x$ refers only to an equal share of what the meter says the fare is, i.e., $x=F/2$. Under this interpretation, the answer is
$$1.1x+2.2$$
for each woman's equal share of the total cost of the ride to the airport.