Finding inverse of a function that is mixture of exponentials

618 Views Asked by At

How can we find the inverse of this function? $$y=\exp(ax)+\exp(bx),$$ where $a$ and $b$ are constants

1

There are 1 best solutions below

0
On

In general, there is no closed form for it. For example, if $a=5$, $b=1$, write $t=e^x$, then you have $t^5+t-y=0$, and it's well-known you can't solve for $t$ in terms of elementary functions.