I'm having problem solving this question and I was hoping someone could help me out a bit. This is what's given:
$g(x)=x^3+x-9$
and I'm supposed to find
$\ g^{-1}\left(1\right) $
Am I supposed to just find the inverse and just plug it in? If so, could someone be kind enough to help me through a bit of the algebra? Is there any easy way of doing this?
$\ x=y^3+y-9 $
Thanks!
This may not involve algebra but still if you want to figure it out quickly then perhaps below can help ,
In $g(x)=x^3+x-9$ , we can just try by trial and error method to make the $x^3+x-9$ term equal to $1$ , so that we can get $g^{-1}(1)$ , if you see that by plugging $x = 2$ we can get $x^3+x-9 = 1$ , so that $g^{-1}(1) = 2$.