How to find the length of the tangent to the circle $x^2+y^2=4$ drawn from the image of origin w.r.t $3x+4y+25=0$.
The options given are
$96$
$\sqrt{96}$
$9\sqrt{6}$
$6\sqrt{8}$
How to find the length of the tangent to the circle $x^2+y^2=4$ drawn from the image of origin w.r.t $3x+4y+25=0$.
The options given are
$96$
$\sqrt{96}$
$9\sqrt{6}$
$6\sqrt{8}$
The tangent is drawn from the reflection of the origin in the line $3x + 4y + 25 = 0$.
I'll leave you to figure out how the lengths relate to the answer $x = \sqrt{10^2 - 2^2} = \sqrt(96)$ in the sketch below.