I'm having trouble evaluating the limit below, without L'Hopital's rule of a rational trigonometric expression.
I've tried applying a number of trigonometric limits, but keep coming up blank
$$ \lim\limits_{x \to 0} \frac{\sin^2(3x)}{1-\cos(2x)} $$
2026-04-02 00:24:06.1775089446
Finding limit without L'Hopital's rule of a rational trigonometric expression
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