Finding the adjacent of a right angle triangle with given height.

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Given the following conditions:

  • A right angled triangle
  • Height is 13
  • Angle a & b are not equal
  • X and Y are not prime numbers.

Is there any math formula to find X,Y, A & B?

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Thank you.

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Your triangle will be a primitive Pythagorean one since one side is $13$ and no right triangle has all three sides equal. It's known that the sides of such are $p^2-q^2,2pq,p^2+q^2$ [last being hypotenuse] where $p,q$ have gcd $1$ and $p>q.$

$13$ is odd so it must be $p^2-q^2=(p-q)(p+q)$ the only way this is $13$ is if $p-q=1,p+q=13$ leading to $p=7,q=6.$ Then the other leg is $2pq=84$ and hypotenuse $85.$ Using a rough approx. in calculator gives $A=8.8$ and $B=81.2$ [degrees] Used arctan for these and rounded.