Finding the altitude of an isosceles triangle with base length and angle

Question

So I have triangle ABC where:

1. $AC = BC$;
2. $AB$ is known
3. $\hat C$ (the angle $A\hat CB$) is known

I'm trying to find the altitude of said triangle.

Answer 1

AB/2tan(∠C/2) should be the answer! The altitude is the angle bisector