How can I find the equation of a plane by its parametric equations?
Like this one:
p: x = h + t y = -1 + 2h - 3t z = -3 + h - t
The exercise is to see if a given straight (r in this case) is contained in the plan (Pi), as the following photo
Could you guys please help me out?
You can write $$x-2=t,\frac{y+2}{2}=t,z+3=t$$ where $t$ is a real number. So we have $$[x,y,z]=[2,-2,-3]+t[1,2,1]$$ That is true, since we have $$t+2-2=\frac{2t-2}{2}=t-3+3=t$$.True!