Finding the integer parts of irrationals

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When working with continued fraction expansions, I sometimes have to calculate the integer part of irrationals quickly without a calculator, what would be an effective way to do this?

For example, how would one quickly and accurately find the integer part of:

i) $\frac{1}{3}\sqrt{5}$

ii) $\frac{1}{4}\sqrt{11}$

iii) $\frac{1}{8}\sqrt{13}$

iv) $\frac{1}{2}(\sqrt{11}+3)$

I can only use working out on paper and I would like a consistent method to use for an upcoming test

Example: for $\sqrt{11}$ I know that $11$ is between $9$ and $16$ so the integer part would clearly be $3$

The same method cannot be as easily applied for when we are working with a fraction of this irrational

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The method works for your examples :

$$2\lt\sqrt 5\lt 3\Rightarrow 0\lt\frac 23\lt\frac{\sqrt 5}{3}\lt \frac 33=1$$ $$3\lt \sqrt{11}\lt 4\Rightarrow 0\lt \frac 34\lt\frac{\sqrt{11}}{4}\lt\frac 44=1$$ $$3\lt\sqrt{13}\lt 4\Rightarrow 0\lt\frac 38\lt\frac{\sqrt{13}}{8}\lt \frac 48\lt 1$$ $$3\lt\sqrt{11}\lt 4\Rightarrow 6\lt\sqrt{11}+3\lt 7\Rightarrow 3\lt\frac{\sqrt{11}+3}{2}\lt\frac 72=3.5$$