I've been struggling trying to work out the following exercise:
Here are some $xy$ and $yz$ cuts I've made when considering the limits of the following shape:
Here's a $xz$ picture of these two objects. I don't know if these two lines are actually creating an enclosed area - as, for instance, I don't know if the general line for $z=4\alpha ^2 + y^2$ even encloses the blue line, but I'm assuming it does since this would make the problem solvable (not a good justification, but..)

Here is the image of the two objects with constant $z$.
Here, I don't know if the general equation for the ellipse is actually even cut by the lines $y = \pm \sqrt{(4/3) - (\alpha/3)}$, so I don't know if the $y$ limit is the upper and lower ends of the ellipse or the equation of the two horizontal lines I specified in the previous sentence.
If these lines are for some constant $alpha$, how can I deduce the volume I'm sketching in? Depending on alpha, this can potentially change the limits, I'd think, as in the case of the second picture. With $alpha$ being sufficiently large, the ellipse is cut by the two lines.


Equate equations $z=4x^2+y^2=4-3y^2$. We get, $x^2+y^2=1$. Use cylindrical cordinate system.
$r:0\to 1$
$\theta:0\to 2\pi$
$z:4-3r^2\sin^2\theta \to r^2+3 \cos^2\theta$
$dxdydz=rdrd\theta dz$