Find the value of $\log_{3} (3^{2x}-3^x+1) = x$. How should we get the value of $x$. $x$ is equal to $0$ but problematically I can't find a way to show that.
2026-05-14 22:50:10.1778799010
finding the methodology of solving logarithmic equation
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1
Look at $3$ raised to both sides, then you get: $$3^{\log_3(3^{2x}-3^x+1)}=3^x$$ Which is the same as $$3^{2x}-3^x+1=3^x$$ Can you take it from here?