In $F_7$, why is $6$ the multiplicative order of $3$ ?
2026-04-11 20:11:44.1775938304
Finding the multiplicative order of elements in $F_7$
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Because (everything is done modulo $\;7\;$ )
$$3^2=2\;,\;\;3^3=-1\;,\;\;3^6=1$$