Finding the partial fraction of $x+21/2(2x+3)(3x-2)$

Question

$x+21 / 2(2x+3)(3x-2)$

The 2 in the denominator represents a problem for me:

$x+21 / 2(2x+3)(3x-2) = A / 2(2x+3) * B / 2(3x-2)$ $x+21 = A(2)(3x-2) + B(2x+3)$

Answer 1

Do it this way:

$$\frac{1}{2}\cdot \frac{x+21}{(2x+3)(3x-2)}=\frac{1}{2}\cdot (\frac{A}{2x+3}+\frac{B}{3x-2})$$ Then continue.