Finding the point of concurrence of a family of straight lines

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If $6a^2-3b^2-c^2+7ab-ac+4bc=0$, then the family of lines $ax+by+c=0$ is concurrent at

  1. $(-2,-3)$
  2. $(3,-1)$
  3. $(2,3)$
  4. $(-3,1)$

Multiple answers are possible.

I am not able to group terms of the expression $6a^2-3b^2-c^2+7ab-ac+4bc=0$ so as to get expression in the form $\lambda_1L_1+\lambda_2L_2=0$, where $L_1$ and $L_2$ denote two lines out of the given family. Please help.