Finding the real potential and streamfunction from a complex potential

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I'm trying to solve the following problem given on a previous exam in my fluid mechanics course:

A stationary flow is given as the following complex velocity potential:

$$ \beta(z) = \ln(z - a) + \ln(z + a) + Uiz $$

Find the real velocity potential and the stream function.

Let's first of all rewrite this as:

$$ \beta(z) = \ln(z^2 - a^2) + Uiz $$

We know that the real velocity potential and the stream function are respectively given as the real and imaginary parts of the complex potential:

$$ \beta = \phi + i\psi $$

We know that a complex logarithm can be rewritten as:

$$ \ln(z) = \ln(r) + i\theta = \frac{1}{2}\ln(x^2 + y^2) + i\arctan2(y,x) $$

With this we can rewrite the complex potential as

$$ \beta (z) = \frac{1}{2}\ln(x^2 - y^2 - a^2 + 4x^2y^2) + i\arctan2(2xy,x^2 - y^2 - a^2) + U(-y +ix) $$

which gives:

$$ \phi = \frac{1}{2}\ln(x^2 - y^2 - a^2 + 4x^2y^2) - Uy, \quad \psi = \arctan2(2xy,x^2 - y^2 - a^2) + Ux $$

Is this correct? I'm having some doubts since I wouldn't expect the somewhat esoteric arctan2 in an answer to an exam problem.