I was wondering on how I can find the turning points of this relation:
$(x^2-7x+5)^2-y^2+7y-5=0$
The relation is two oval shapes that are seperated. Theres a desmos graph.
https://www.desmos.com/calculator/kfr2po2xxm
Thanks Braiden
I was wondering on how I can find the turning points of this relation:
$(x^2-7x+5)^2-y^2+7y-5=0$
The relation is two oval shapes that are seperated. Theres a desmos graph.
https://www.desmos.com/calculator/kfr2po2xxm
Thanks Braiden
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