What is the x-intercept of $|x-12|+8$? I don't know how to solve it with the absolute values and whether there will be two answers.
2026-04-04 13:46:28.1775310388
Finding x-intercept of absolute values
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1
It doesn't have one, for if $|x - 12| + 8 = 0$, then $|x - 12| = -8 < 0$, which isn't possible.