Finite dimension of $X/M$ and closed complement

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I just did an exercise that goes like this

Let $X$ be a normed vector space and $M$ a closed subspace such that $dim (X/M)<\infty$, show that there exists a closed subspace $N$ such that $X=M\bigoplus N$.

Now my touhgt processe was well we know that every subspace of a normed vector space has an algebraic complement $N$ such that $X=M\bigoplus N$, and since $N \cong X/M$ we will have that $N$ has finite dimension and so it will be closed. Now do we need the fact that $M$ is a closed subspace of $X$, am I forgetting of justifying something?