$$\mathcal{L}(e^{3t}\sin(5t)\sin(3t))$$$$f(t)=e^{3t}\sin(5t)\sin(3t)$$
Transform the product into a sum
$$\sin(5t)\sin(3t)=\frac12 ( \cos (2t)-\cos (8t))$$
So that we have:
$$f(t)=\frac 12e^{3t} \cos (2t)-\frac 12 e^{3t}\cos(8t)$$$$\mathcal{L}(f(t))=\frac 12\mathcal{L}(e^{3t} \cos (2t))-\frac 12 \mathcal{L}(e^{3t}\cos(8t))$$
Apply the following formula:
$$\mathcal{L}(e^{bt} \cos (at))=\dfrac {(s-b)}{(s-b)^2+a^2}$$
$$\mathcal{L}(e^{3t}\sin(5t)\sin(3t))$$ $$f(t)=e^{3t}\sin(5t)\sin(3t)$$ Transform the product into a sum $$\sin(5t)\sin(3t)=\frac12 ( \cos (2t)-\cos (8t))$$ So that we have: $$f(t)=\frac 12e^{3t} \cos (2t)-\frac 12 e^{3t}\cos(8t)$$ $$\mathcal{L}(f(t))=\frac 12\mathcal{L}(e^{3t} \cos (2t))-\frac 12 \mathcal{L}(e^{3t}\cos(8t))$$ Apply the following formula: $$\mathcal{L}(e^{bt} \cos (at))=\dfrac {(s-b)}{(s-b)^2+a^2}$$