I'm trying to solve this problem:
Set up an integral to compute the volume of the solid inside the cone $x^2 = y^2 + z^2$, with $|x| \geq 1$, in a coordinate system of your choice.
Since the cone is along the $x$-axis, I'm not sure how to set up my triple integral. I cannot use rectangular, spherical, or cylindrical, because the shadow/projection I'd use to find the bounds would be in the $xz$-plane. How should I solve this? TIA