For every $a$ in $\mathbb N^+$, prove that there exist a natural number $b$ such that $b++=a$.

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The question is listed above. The question is that whether$\forall a\in \mathbb{N^+}, \exists b\in \mathbb{N} \,,s.t.a=b++$ is right.

My question is, in my proof, I’ve tried to use the mathematical induction, but as I assume that if the number $n$ satisfies the situation, the element $n++$ could easily make sense, so I’m wondering whether the mathematical induction could make sense.

The question is quite trivial but I’m really caught in trouble. Hoping for help.