For which values of x does the sequence $a_n$ converge? (ratio test for $a_n=\frac{x^n}{n^3}$)

542 Views Asked by At

I was wondering if anyone could offer any tips or hints as to how to tackle this question, I've tried looking around on here and in my notes but I can't seem to find anything.

Consider the sequence

$$ {a_n=\frac{x^n}{n^3}}. $$

B1. Apply the ratio test to find out for which values of $x$ the sequence $(a_n)$ converges.

B2. For which value(s) of $x$ does the ratio test provide no information?

B3. Does $(a_n)$ converge or diverge for these values? Justify your answers.

B4. Give an example of a sequence that converges if $-1<x<1$ and diverges otherwise. Justify your answer.

1

There are 1 best solutions below

3
On

By ratio test we obtain

$$\left|\frac{x^{n+1}}{(n+1)^3}\frac{n^3}{x^n}\right|=|x|\left(\frac n{n+1}\right)^3 \to |x|$$

then for convergence we need $|x|<1$, then study separately the cases $|x|=1$.