for which values of x this function is discontinuous?

Question

I've only found x is discontinuous when = -2 and -3, but i'm no pretty sure if is the same for x<-3

Answer 1

$$\lim_{x\to -3,x<-3}f(x)=f(-3^-)=3$$ $$f(-3^+)=-1=f(-3)$$

thus $f$ is continuous on the right of $-3$ and discontinuous on the left.

$$f(2)=4$$ $$f(2^-)=f(2^+)=2\ne f(2)$$

$f$ is discontinuous at $x=2$.