Formula to calculate the average diameter of a mixture of two sizes of marbles.

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Im looking to mix two particle sizes of powder metals, and need to calculate the resultant average particle size.

O.K. More specifically: I mix 50 pounds of metal powder that has a spherical particle size of 6 microns with 50 pounds of metal powder that has a spherical particle size of 0.8 micron. What is the resultant average particle size? All have the same density. By volume, 1 large particle is 419 times larger than a small particle, so there are 419 times more small particles than large particles. D(avg) = .5D(1) + .5D(2) does not work. The mixture is much finer because of the large size difference between the two particle sizes. I need to know the average particle size.