What will the Fourier series of function $\sin 2x$ between the limits $-\pi<x<\pi$ be?
2026-04-12 15:09:16.1776006556
FOURIER SERIES trigonometric functions
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If you have a function $\phi (x)\in L^2(a,b)$, then you can rewrite it in terms of basis functions of Fourier space. The basis functions are $sin(nx)$ and $cos(nx)$. Now you have, $sin(2x)$, that is already one of basis of Fourier series. So you have the solution!