- Given a signal $\,\mathrm{M}\left(\, f\, \right) = A$ for $\left\vert\, f\, \right\vert < B$ and $0$ else, what will be the expression for $$ \mathrm{z}\left(\, t\, \right) = \,\mathrm{m}\left(\, t\, \right) \cos\left(\, 2\pi\,\left[\, 1.9 \times 109\,\right]t + {\pi \over 4}\,\right)\ ?. $$
- So i have used the inverse fourier transform for $\,\mathrm{M}\left(\, f\,\right)$ to find $\,\mathrm{m}\left(\,t\,\right)$. I am not sure but i think it gave me A(delta) $\left[\,\mbox{IFT for constant}\,\right]$.
- The simplifying the $\cos$ term to Euller's formula should give what ?.
I am not sure though. and i am stuck in finding $\,\mathrm{m}\left(\,t\,\right)$. Thanks in advance for the help.
By "the expression" for it you are referring to its Fourier transform right?
First, $M(f)$ is not a constant. It is a rectangular function.
Following these steps, you will get to $$Z(f)=\frac{A}{2}\left(e^{−j\frac{\pi}{4}}\frac{B}{2}\text{sinc}\frac{B}{2}(f+f_0)+e^{j\frac{\pi}{4}}\frac{B}{2}\text{sinc}\frac{B}{2}(f-f_0)\right)$$ where $f_0=1.9\times109$.