Find the fourier transform for signal in this picture (sorry for the bad quality)
Could it be done like this? The signal is a sum of two triangular waves that are each delayed. $$x(t)=A\Lambda\left( \frac{t+T/2}{T}\right)-A\Lambda\left( \frac{t-T/2}{T}\right)$$ And the fourier transform for delayed signal $F\{x(t+t_d)\}=X(f)\cdot e^{-i2\pi ft_d}$. And the fourier transform for triangular pulse is defined $F\{ \Lambda(t/T)\}=T \operatorname{sinc}^2(\pi fT) $ \begin{align} F\{x(t)\}&=AT \operatorname{sinc}^2(\pi fT)\cdot e^{-i2\pi f (-\frac{T}{2})} -AT \operatorname{sinc}^2(\pi fT)\cdot e^{-i 2 \pi f \frac T2} \\ &=AT \operatorname{sinc}^2(\pi fT)\cdot (e^{i\pi f T} - e^{-i \pi f T}) \\ &=AT \operatorname{sinc}^2(\pi fT)\cdot2i\sin(\pi f T) \end{align}
Is this solution valid?