Fourth root in denominator for derivatives

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The problem I'm working with right now looks like this

$$\dfrac{(6x^3 + x)(4x-2x^2)}{3 \cdot x^\frac14}$$

How do I deal with the fourth root in the denominator to find the derivative? This problem's really driving me crazy.

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Hint:

After expanding/rewriting you get $$-\dfrac{\left(4x-2x^2\right)\left(6x^3+x\right)}{12x^\frac{5}{4}}+\dfrac{\left(4-4x\right)\left(6x^3+x\right)}{3\sqrt[4]{x}}+\dfrac{\left(4x-2x^2\right)\left(18x^2+1\right)}{3\sqrt[4]{x}}$$ Can you continue?