$\frac{\sqrt{26} - \sqrt{13} - \sqrt{2}+1}{\sqrt{13} -1 }= ? $

Question

$$\frac{\sqrt{26} - \sqrt{13} - \sqrt{2}+1}{\sqrt{13} -1 }= ? $$

My attempt:

$$\frac {\sqrt{2}. \sqrt{13} - \sqrt{13}-2 +1}{2} \tag 1$$ Which equals to $$\frac {\sqrt{2}-1}{\sqrt{13} +1} \tag 2 = ...$$

Waiting for your helps.

Answer 1

\begin{align}\frac{\sqrt 2 \cdot \sqrt{13}-\sqrt{13}-\sqrt2+1}{\sqrt{13}-1}&=\frac{\sqrt{13}(\sqrt 2 -1)-1 (\sqrt2-1)}{\sqrt{13}-1}\\&=\frac{(\sqrt{13}-1)(\sqrt 2-1)}{\sqrt{13}-1}\\&=\sqrt2-1 \end{align}

Answer 2

$$\dfrac{\sqrt 2-1}{\sqrt{13}+1}=\dfrac{\sqrt 2-1}{\sqrt{13}+1}\dfrac{\sqrt {13}-1}{\sqrt{13}-1}=\dfrac{1}{12}(\sqrt2-1)(\sqrt{13}-1)=\dfrac{1}{12}(\sqrt{26}-\sqrt{13}-\sqrt{2}+1)$$