Fractional integration in terms of shift operator

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I am trying to understand the fractional derivation and fractional integration. I found a representation of the fractional derivation operator in term of shift operator that is:

$D^n=(1-S)^n = \sum_{k=0}^{+\infty}\frac{\Gamma(k-n)S^k}{\Gamma(-k)\Gamma(n+1)}$

If I define the integration as the inverse of derivation, I must have

$I\cdot D = 1$

where I define $I$ as the integration operator.

So, my question is can I have a representation of the fractional integration in terms of operator $S$ as

$I^n\cdot D^n = D^{-n}\cdot D^n = 1$

namely

$I^n = \sum_{k=0}^{+\infty}\frac{\Gamma(k+n)S^k}{\Gamma(-k)\Gamma(-n+1)}$ ?