Let's say we have x, which is any decimal number between 0.5 and 1.
What function can be applied to it such that an input of 0.5 equals 0 and input of 1 equals 1? It should be linear.
I tried something like this:
f(x) => x / 2 + 0.5
Which works for 1, but not 0.5. Apparently my math skills are lacking... What is the approach to figure out problems like this in general?
PS - for the curious, this is the value of the opacity of a label while paging items in an iPad app.
Suppose the function we want to find is $f(x)$. Since it should be linear, we have $f(x)=ax+b$. Suppose we want $f(x_0)=y_0$ and $f(x_1)=y_1$. That can be rewritten to $$ ax_0+b=y_0\\ ax_1+b=y_1 $$ Solving that for $a$ and $b$ yields $$ a=\frac{y_0-y_1}{x_0-x_1}\\ b=y_0-ax_0 $$ In your case, we have $f(\frac 12)=0$ and $f(1)=1$. That gives $$ a=\frac{1-0}{\frac 12-0}=\frac 1{\frac 12}=2\\ b=0-2\frac 12=-1\\ f(x)=ax+b=2x-1 $$